Random thought of the moment...

Here's how you'd actually prove that 1 = 0! :sick:

0 = 0 + 0 + 0 + 0..., right? Yes!

and also 0 = (1 - 1), correct? Totally!

so than I can write;

0 = (1 - 1) + (1 - 1) + (1 - 1) + ...

Now I simply apply the associate law of addition to that, and get;

0 = 1 + (-1 + 1) + (-1 + 1) + (-1 + 1) + ...

And that's what?

0 = 1 + 0 + 0 + 0 + ...

Which is... Yeap! Ta ta!

1 = 0
 
What about it? Everyone knows 2 = 1. Here;

Assume that x and y are the same number. For example; x = 1 and also y = 1. So I could write down x = y and it'd be valid.

So now I'm really writing it, LOL;

x = y

Since x and y are the same crap, I can represent the above equation as;

x2 = xy (as in X squared equals X times Y)

Now, I sustract y2 from both sides of the equation.

x2 - y2 = xy - y2

Everyone here who ever learned algebra will agree that x2 - y2 factors as (x + y)(x - y). And we can also factor xy - y2 like this:

(x + y)(x - y) = y(x - y)

All correct? Absolutely! Now, we have (x - y) on each side, it's the common term. We can devide each side by (x - y) and simplify the equation. That leaves us;

x + y = y

I've said x and y are both 1, yeah? So;

1 + 1 = 1

2 = 1

Ta ta! :D
 
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