Quote:
Originally Posted by Marksman
somebody actually dug this out,well ok,heres one new
some tauthology
investigate if these formulas are correct using real numbers
a) (Ax)(Ey)(x<z)
b) (Ax)(Ey)(xy=x)
Godluck and do some kick-ass math 
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Hmm, for the b-tauthology I would say that it is true. Since it would say something like "for all X there is (at least) one Y that makes the expression XY=X" And if Y = 1 the expression is true.
For the a-tautology I would say it is false.