Originally Posted by Chukpike

What a sniper does by compensating for the environment when taking a shot is amazing in the complicity of the problem. The human brain solves the equation in real time, digital computers can't.

I think that you have summed it up pretty well.

I once hit a running wild dog in the bum at about 800 yards* offhand with an M1 Garand in three shots. I have always put it down as a lucky shot, but there must be an element of skill somewhere as I was told, both the previous shots kicked up dirt that partially obscured him to my mate who was spotting for me through his binoculars.

*(thats what I cranked on the sights)

I would not like to be expected to repeat it any time soon,... but I would certainly enjoy trying.

Originally Posted by Chukpike

And the math required doesn´t belong on an open board.

Why? It is not secret.

.

Agreed, not secret.
As TI pointed out there is a phone app called bulletflight that do it for you.
And if you happen to have KAC it even fills in some of the numbers of your formula.


Why would anyone not in the field need to know what the equation contains?

And I stand by my statement at 2500 meters you would be the best shot in the world..
As the current record stands at 2430 meters.

//KJ.

The thing is to even post the simple stuff like bullet rise/fall windage and elevation adjustments mil forumla and range estimation would take pages. It's not as easy as dialing in a scope. Different rounds within the same caliber in different enviroments react differently, past a certain range spin drift is a problem. It's not a one blurb answer.

KJ: I thought Hurlong bracketed, one low one high and one on target.

Hmm. I thought that shot was 2 miles, I must have misread.

Okay so say 1500 metres?

And why not give me the math? I can't use it,I doubt my bow, which is the only projectile weapon I have, needs it, I just want to see how it works.

And I realize it's not one blurb there is windage, humidity, angle of fire, arc of bullet, gravity, heat and I probably missed some. The ones I am most interested in are windage, angle and arc.

Originally Posted by 03USMC

KJ: I thought Hurlong bracketed, one low one high and one on target.

Not what I heard, first one missed, adjusted second one hit.
Though I might be misinformed cause I haven´t gotten this from the shooter himself.

//KJ.

Originally Posted by TheManFromOz

Hmm. I thought that shot was 2 miles, I must have misread.

Okay so say 1500 metres?

And why not give me the math? I can't use it,I doubt my bow, which is the only projectile weapon I have, needs it, I just want to see how it works.

And I realize it's not one blurb there is windage, humidity, angle of fire, arc of bullet, gravity, heat and I probably missed some. The ones I am most interested in are windage, angle and arc.

Here are some terms you will need in understanding some of the formulas.
Notation



In the equations on this page, the following variables will be used:

• g: the gravitational acceleration—usually taken to be 9.81 m/s2 near the Earth's surface
• θ: the angle at which the projectile is launched
• v: the velocity at which the projectile is launched
• y0: the initial height of the projectile
• d: the total horizontal distance traveled by the projectile

Distance traveled
The total horizontal distance (d) traveled.
When the surface the object is launched from and is flying over is flat (the initial height is zero), the distance traveled is:
As a special case, the distance is given by
when the angle (θ) is 45° and the initial height (y0) is 0.
For explicit derivations of these results, see Range of a projectile.

If you wish to learn more you will have to take Calculus and advanced Algebra. You will also have to have had geometry which is relatively easy.

This is basic stuff that I have posted from Wikipedia.

Everything that applies to a bullet traveling threw air, also applies to arrows.

Originally Posted by KJ

Not what I heard, first one missed, adjusted second one hit.
Though I might be misinformed cause I haven´t gotten this from the shooter himself.

//KJ.

Or I could be...my info is also second hand.

That is without including the ballistic coeficient of the projectile, windage or air temperature (Density). There's probably more, like Coriolis force?

Redleg would probably know, if not, he'd know where you can find the necessary formulae. At the range you quote this is almost becoming an artillery question.

Originally Posted by TheManFromOz

Hmm. I thought that shot was 2 miles, I must have misread.

Okay so say 1500 metres?

And why not give me the math? I can't use it,I doubt my bow, which is the only projectile weapon I have, needs it, I just want to see how it works.

And I realize it's not one blurb there is windage, humidity, angle of fire, arc of bullet, gravity, heat and I probably missed some. The ones I am most interested in are windage, angle and arc.

Depends on alot of things, Weapon, Caliber, Enviroment...you want an easy answer....but the varibles don't lend them self to that.

KJ is right Hurlongs shot with a McMillian .50 right at 1 1/2 miles.

Thanks for that, I should checked wikipedia.

It applies to arrows, yes, but the furthest I can send an arrow is 300 metres maybe more with an ultra modern high poundage compound, maybe 400. At that range, I don't need maths, its just about impossible for me to judge with any accuracy anyway (I am not a master of the bow by any means) because there are far more variables than with firearms. At the ranges I use my bow, usually twenty to sixty metres, I only need instinct or whatever you want to call it.