Originally Posted by Marksman

somebody actually dug this out,well ok,heres one new
some tauthology
investigate if these formulas are correct using real numbers

a) (Ax)(Ey)(x<z)
b) (Ax)(Ey)(xy=x)

Godluck and do some kick-ass math

Hmm, for the b-tauthology I would say that it is true. Since it would say something like "for all X there is (at least) one Y that makes the expression XY=X" And if Y = 1 the expression is true.

For the a-tautology I would say it is false.

sorry peace keeper,rotc boy got it before u,even if i think he was taking a blind shot u win rotc

next math problems will be submited as soon as i get some millbucks to give away,im on ground 0 now.....................

holy crap i won?!

i just guessed, yay!!!